In how many ways can three pairs of siblings from different families be seated in two rows of three chairs, if siblings may sit next to each other in the same row, but no child may sit directly in front of their sibling?
There are only 2 * 2 * 2 ways for the case where each sibling sits directly in front of their sibling, which is what we do not want. Thus, we will subtract that from the total number of cases, 6! 6! = 720 720 - 2^3 = 720 - 8 = 712 ways
+2653 
