When the digits in the number 2005 are reversed we obtain the number 5002 and 5002=a*b*c such that a, b and c are three distinct primes. What are a, b, and c?

Guest Jul 7, 2021

#1**0 **

Just do the prime factorization of 5002. We get 2, 41, 61. So those are the three primes.

Awesomeguy Jul 7, 2021