Completely simplify and rationalize the denominator: $$\frac{\sqrt{160}}{\sqrt{252}}\times\frac{\sqrt{245}}{\sqrt{360}}$$
+118609 Hint:
Think about 160, an obvious square number that goes into 160 is 16. So you can do this.
\(\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}\)
Now simplify all the other squareroots yourself and then get back to us.
+677 Hi Melody,
\( \sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}\)
\(\sqrt{245}=\sqrt{49*5}=\sqrt{49}*\sqrt{5}=7\sqrt{5}\)
\(\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}\)
\(\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}\)
Now Guest can do it from here.
Hope that was helpful.^^
Straight
