let f(x)=x^2-7x+12 and g(x)=x^2-9
what is (f/g)(x)?
x-4/x+3 where x ≠ -3,3
x+3/x-4 where x ≠ 3,4
x-4/x-3 where x ≠ -3,4
x+4/ x-3 where x ≠ -3,3
f(x) = x^2 - 7x + 12.......factor as (x -3) ( x - 4)
g(x) = x^2 - 9....factor as ( x -3) ( x + 3)
So
(f / g) (x) = f(x) / g( x) = (x - 3) ( x - 4 ) x - 4
___________ _= ______ where x ≠ -3,3
( x - 3) ( x + 3) x + 3
