+55 If I have 5 moles of P4O6 (approx 1099.45 grams), what is the weight (in grams) of phosphorus in this compound? Please explain because I'm very confused.
Convert from moles into grams:
5 mol of P4O6 (tetraphosphorus(III) hexoxide)
Split the chemical formula P4O6 into a tally of its elements:
atom | tally
O | 6
P | 4
Using the atomic masses of the elements O (15.999 u) and P (30.973761998 u), calculate the total mass of each element in 1 molecule of P4O6:
atom | tally | atomic mass | mass in molecule
O | 6 | 15.999 u | 95.994 u
P | 4 | 30.973761998 u | 123.89504799 u
Calculate the molecular mass of P4O6 by adding the mass of each type of atom:
95.994 u + 123.89504799 u = 219.89 u
Since 1 u corresponds to 1 g/mol, the molar mass of P4O6 equals 219.89 g/mol. The number of grams equals the molar mass of P4O6 multiplied by the molar amount:
(5 mol) * 95.994 =479.97 grams of Oxygen + (5 mol)* (123.895 g/mol) =619.475 grams of Phosphorus =1,099.45 grams in 5 moles of P4O6
+37146 P = 30 . 97696 x 4 = 123.9078
O=15.9994 x 6 =95.9964
123.9078 / (123.9078 +95.9964) * 1099.45 = 619.498 gm of P
