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Solve:

\(y'' - \omega^2y = 0, y(0)=1,y'(0)=1\\\text{Assuming }\omega \neq 0 \)

MaxWong  Jul 25, 2017
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Like so:

 

\(y=Ae^{\omega x}+Be^{-\omega x}\\ y'=\omega Ae^{\omega x}-\omega Be^{-\omega x}\\ y''= \omega^2y\)

 

Now use your initial conditions to find A and B.

Alan  Jul 25, 2017

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