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# Need some help with differential equations.

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Solve:

$$y'' - \omega^2y = 0, y(0)=1,y'(0)=1\\\text{Assuming }\omega \neq 0$$

Jul 25, 2017

#1
+27365
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Like so:

$$y=Ae^{\omega x}+Be^{-\omega x}\\ y'=\omega Ae^{\omega x}-\omega Be^{-\omega x}\\ y''= \omega^2y$$

Now use your initial conditions to find A and B.

Jul 25, 2017