The reaction is C7H16(L) + 11O2 = 7CO2 + 8H2O
Heat of combustion for one mole C7H16 is -4.85*10^3 KJ
Using the information given, calculate \(\Delta H\) ºf for C7H16 in kJ/mol
\(\Delta H\) ºf CO2 = -393.5 kJ/mol
\(\Delta H\) ºf H2O = -285.8 kJ/mol
I was actually able to solve this myself. The heat for formation of one mole c7h16 = -187.4 kJ/mol.
Please mark as completed.