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# Need some help with this question. Thank you.

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A company spent \$9.065 on some wallets and bags. The ratio of the number of wallets bought to he number of bags bought was 5:7. A wallet cost \$13.30 more than a bag. The total cost of the wallets was 17/20 of the total cost of the bags. Find the cost of one such wallet.

Aug 26, 2021

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Given:

Ratio of wallet & bags = 5:7

Wallet cost = \$13.30 more than a bag

Total spenditure by company = \$9.065

Total cost of wallet = 17/20 of total cost of bag

To find:- Cost of one wallet

Let cost of one bag is y

Cost of wallet = \$(13.30+y)
No of wallets         5

------------------ =  ------ = Let 5x/7x

No of bags            7

Total cost of bag = 7x * y

Total cost of wallet -(13.30+y) * 5x

Now Total cost of wallet = 17/20x Total cost of bag

(13.30+y) * 5x = 17/20 * 7y

(13.3+y) * 100 = 119y

1330 + 100y = 119y

1330 = (119-100)y

19y = 1330

y = 70

So Cost of one bag = \$y = \$70

Cost of one wallet = \$(13.30 + y) = \$(13.30 + 70)

= \$83.30

Nov 4, 2021