If the polynomial x^2+bx+c has exactly one real root and b=c+1, find the value of the product of all possible values of c.
never mind i found the answer its 1 btw
x^2+bx +c ... b = c + 1 ....so....
x^2 + (c + 1)x + c
If this has one real root, the discriminant = 0
So
(c + 1)^2 - 4(1)(c) = 0 simplify
c^2 + 2c + 1 - 4c = 0
c^2 - 2c + 1 = 0 this factors as
(c - 1)^2 = 0 take the square root
c - 1 = 0 ⇒ c = 1
+68 
