A ball is thrown from a height of 15 m above the ground. The height (in metres) of the ball at time t seconds after is thrown is given by the function h(t) =-5t² +22t +15, where t ≥ 0
Determine the time that the ball hits the ground and its velocity when it hits the ground.
+1224 The ball hits the ground when the height is 0, so we are solving the equation \(-5t^2+22t+15=0.\)
Using the quadratic equation, we get \(t= -\frac{3}{5}, 5\). Time can't be negative, so the ball hits the ground after 5 seconds.
I am unsure about the second part, but I hope this gets you started.
