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 A ball is thrown from a height of 15 m above the ground. The height (in metres) of the ball at time t seconds after is thrown is given by the function h(t) =-5t² +22t +15, where t ≥ 0

 

 

 

Determine the time that the ball hits the ground and its velocity when it hits the ground.

 Feb 20, 2021
 #1
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The ball hits the ground when the height is 0, so we are solving the equation \(-5t^2+22t+15=0.\)

 

Using the quadratic equation, we get \(t= -\frac{3}{5}, 5\). Time can't be negative, so the ball hits the ground after seconds.

 

I am unsure about the second part, but I hope this gets you started.

 Feb 20, 2021
 #2
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sorry how did you calculus t=-3/5 and 5 

Guest Feb 20, 2021

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