Arc \(AC\) is a quarter-circle with center \(B\). The shaded region \(ABC\) is "rolled" along a straight board \(PQ\) until it reaches its original orientation for the first time with point \(B\) landing at point \(B^{\prime}\). If \(BC = \frac{2}{\pi}\) cm, what is the length of the path that point \(B\) travels? Express your answer in simplest form.
First it travels one more radius, then the circumference. then one more radius. So, we have $\frac{2}{\pi}+\frac{\pi*2*\frac{2}{\pi}}{4}+\frac{2}{\pi}=\frac{4}{\pi}+\frac{2*2}{4}=\boxed{1+\frac{4}{\pi}}$
Sorry, that is wrong because the point B is supposed to travel on a curved path, not just including the start and endpoints.