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Let $a$ and $b$ be real numbers such that $a+b=-1$. Compute $a^2-b^2+a-b$.

 Mar 27, 2021
 #1
avatar+309 
+1

Nvm, I found out.

$a^2-b^2$ factorizes as $(a-b)(a+b)$. So the full expression factorizes as$$(a-b)(a+b)+(a-b)=(a-b)(a+b+1)$$Since $a+b=-1$, we have that $a+b+1=0$. So the product is $0$. smiley

 Mar 27, 2021
edited by WillBillDillPickle  Mar 27, 2021
 #2
avatar+106 
+2

Good job angel

TealSeal  Mar 27, 2021
 #3
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+1

I was trying to figure it out I'm glade you found out Lol

 Mar 27, 2021

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