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My grandpa has 10 pieces of art, including 3 prints by Escher. If he hangs the pieces of art in a row in a random order, what is the probability that all three pieces by Escher will be placed consecutively?

 Dec 29, 2016

Best Answer 

 #2
avatar+129630 
+6

Total arrangements possible  = 10!

 

Arrangements where the three prints are together  =

 

They can occupy any of 8 positions...and for each of these, they can be arranged in 3! ways.....and the other prints can be arranged in 7! ways......so we have

 

8 * 3!  * 7 !

 

So....the total probability  is :

 

[ 8 * 3! * 7! ]  /  10!    =      [8 * 6] / [10 * 9 * 8 ]  = 6  / 90   =  1 / 15

 

 

 

cool cool cool

 Dec 29, 2016
 #1
avatar+355 
+11

8C1 / 10C3 = 8 / 120 = 1/15

(Tell me if you need more explaining!)

 Dec 29, 2016
 #2
avatar+129630 
+6
Best Answer

Total arrangements possible  = 10!

 

Arrangements where the three prints are together  =

 

They can occupy any of 8 positions...and for each of these, they can be arranged in 3! ways.....and the other prints can be arranged in 7! ways......so we have

 

8 * 3!  * 7 !

 

So....the total probability  is :

 

[ 8 * 3! * 7! ]  /  10!    =      [8 * 6] / [10 * 9 * 8 ]  = 6  / 90   =  1 / 15

 

 

 

cool cool cool

CPhill Dec 29, 2016

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