We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

#1**+2 **

Hey, RP....good to see you !!!

First one

We have a quadrilateral inscribed in a circle (a cyclic quadrilateral).....whenever this is so....the opposite angles in the quadrilateral are supplementary (the sum to 180°)

So

A + C = 180

A + 101 = 180 subtract 101 from both sides

A = 79°

Smillarly

B + D = 180

B + 68 = 180

B = 180 - 68

B = 112°

CPhill Feb 26, 2019

#2**+1 **

These are all answered so differently. How am I supposed to know which formula to use for each problem?

RainbowPanda
Feb 26, 2019

#3**+2 **

Second one

Notice that angle Q intercepts arc PSR

And the measure of this arc= 137 + 41 = 178°

And because angle Q is an inscribed angle intercepting this arc...it measures (1/2)(arc PSR) = (1/2)(178) = 89°

We have a cyclic quadrilateral....R is supplemental to 57° = 180 - 57 = 123°

And S is supplemental to Q = 180 - 89 = 91°

CPhill Feb 26, 2019