Joe had $475 more than Nigel at first. After Nigel spent 60% of his money and Joe spent 85% of his money to buy a present together for their friend, they were left with an equal sum of money. How much did the present cost?

Guest Jul 14, 2022

#1**+1 **

Let Nigel's money ==N

Joe's money ==475 + N

N - 0.60N ==0.40N - what Nigel has left

0.15 * [475 + N]==71.25 + 0.15N - what Joe has left

0.40N ==71.25 + 0.15N, solve for N

0.40N - 0.15N ==71.25

0.25N ==71.25

**N ==71.25 /0.25 ==$285 - what Nigel started with**

**$285 + $475 ==$760 - what Joe started with.**

**Nigel spent: 285 x 0.60 ==$171 - money spent to buy a present.**

**Joe spent ==760 x 0.85==$646 - money spent to buy a present.**

**[285 - 171] ==[760 -646]**

** $ 114 == $114 - what both had left at the end.**

Guest Jul 14, 2022

#2**+1 **

Nigel have x money at first. Then Joe have (x + 475) money at first.

x - 60%x = x + 475 - (x + 475) * 85%

0.4x = x + 475 - 0.85x - 403.75

0.4x = 0.15x + 71.25

0.25x = 71.25

x = 285

x + 475 = $760.

285 * 60% + 760 * 85% = $817

The present cost $817

Slimesewer Jul 14, 2022