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# Not sure where to start

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Joe had \$475 more than Nigel at first. After Nigel spent 60% of his money and Joe spent 85% of his money to buy a present together for their friend, they were left with an equal sum of money. How much did the present cost?

Jul 14, 2022

#1
+1

Let Nigel's money ==N

Joe's money ==475 + N

N - 0.60N ==0.40N - what Nigel has left

0.15 * [475  +  N]==71.25  +  0.15N - what Joe has left

0.40N ==71.25  +  0.15N, solve for N

0.40N - 0.15N ==71.25

0.25N ==71.25

N ==71.25 /0.25 ==\$285 - what Nigel started with

\$285 + \$475 ==\$760 - what Joe started with.

Nigel spent: 285  x  0.60 ==\$171 - money spent to buy a present.

Joe spent ==760  x  0.85==\$646 - money spent to buy a present.

[285 - 171] ==[760 -646]

\$ 114 == \$114 - what both had left at the end.

Jul 14, 2022
#2
+1

Nigel have x money at first. Then Joe have (x + 475) money at first.

x - 60%x = x + 475 - (x + 475) * 85%

0.4x = x + 475 - 0.85x - 403.75

0.4x = 0.15x + 71.25

0.25x = 71.25

x = 285

x + 475 = \$760.

285 * 60% + 760 * 85% = \$817

The present cost \$817

Jul 14, 2022