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Joe had $475 more than Nigel at first. After Nigel spent 60% of his money and Joe spent 85% of his money to buy a present together for their friend, they were left with an equal sum of money. How much did the present cost?

 Jul 14, 2022
 #1
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+1

Let Nigel's money ==N

Joe's money ==475 + N

 

N - 0.60N ==0.40N - what Nigel has left

 

0.15 * [475  +  N]==71.25  +  0.15N - what Joe has left

 

0.40N ==71.25  +  0.15N, solve for N

0.40N - 0.15N ==71.25

0.25N ==71.25

 

N ==71.25 /0.25 ==$285 - what Nigel started with

$285 + $475 ==$760 - what Joe started with.

 

Nigel spent: 285  x  0.60 ==$171 - money spent to buy a present.

Joe spent ==760  x  0.85==$646 - money spent to buy a present.

 

[285 - 171] ==[760 -646]

 $ 114 == $114 - what both had left at the end.

 Jul 14, 2022
 #2
avatar+231 
+1

Nigel have x money at first. Then Joe have (x + 475) money at first.

x - 60%x = x + 475 - (x + 475) * 85%

0.4x = x + 475 - 0.85x - 403.75

0.4x = 0.15x + 71.25

0.25x = 71.25

x = 285 

x + 475 = $760.

285 * 60% + 760 * 85% = $817

The present cost $817

 Jul 14, 2022

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