+39 (37865416541564189641465845164865616581065746784164896415046741654896+17*(358496486157486586578465187415815867416584165786684165841685860)+17*(46468455847465469641587467415874158146587864154187416584156878416541674164))
-
293283293281298283288289313285213213213311240213436370370438391916798025581875215151011042762403461652339064270446680082285083569843868344
293283293281298283288289313285213213213311240213436370370438391916798025581875215151011042762403461652339064270446680082285083569843868344
/
789963787278423965735853859507539761543679141433014796913936978947258775304=
371261693262820578285883718515964922009720840788534508160147511
371261693262820578285883718515964922009720840788534508160147511*
789963787278423965735853859507539761543679141433014796913936978947258775304
-
293283293281298283288289313285213213213311240213436370370438391916798025581875215151011042762403461652339064270446680082285083569843868344
=
0
I generated first expression (378 etc.) by typing random numbers on my keyboard (apart from "17*"). Then, I got a number (7899 etc.) that is exactly divisible by initial i.e. remainder=0! How it can be done for another number?
