number of unique triad combinations equals 528.
What is the number of unique items that makes a total of 528 unique combinations (order does not count as a combination, so ABC is the same combination as CAB)?
I found a formula for finding the number of combinations for a specified number of unique items when the number of items in a set is also specified, however that formula uses factorials and I don't know how to work around that when I don't know one of the variables.
+9479 I think this is basically your question:
\(528=\frac{n!}{3!(n-3)!}\)
And you're trying to solve for n.
I would just try plugging in different values for n until you find the right one.
First I tried 5, that gave me 10.
Next I tried 15, that gave me 455.
Next I tried 16, that gave me 560.
....Well... I don't think that n should have a fraction....I don't know, but maybe this helps some anyway.
