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Find the smallest number which gives remainders 1, 2, 3, 4, and 5 when divided respectively by 2, 3, 4, 5, and 6.

 Jul 9, 2020
 #1
avatar+27660 
+1

I think it might be 59

 Jul 9, 2020
 #2
avatar+752 
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any reasoning, EP, this is the first time i saw you guess since i came to this website!!??

 Jul 9, 2020
edited by whymenotsmart  Jul 9, 2020
 #3
avatar+27660 
+1

Well... it has to be an odd number because when divided by 2  there is a remainder

 

it has to be a multiple of 5   + 4         so I started at  9    then 14   then 19   until I got a 'system' in mind....and thought 59 was the answer....  it works....I didn't check all of the lower numbers that were   multiples of 5  +4

 

 

Oh yah....I GUESS (in an educated way, I suppose) on answers sometimes...particularly probability questions....then I usually enclose an    '(I think) '   !   cheeky       I DO NOT know all of the answers....sometimes I 'try'....which is just slightly better than 'guessing'      HaHa

ElectricPavlov  Jul 9, 2020
 #4
avatar+752 
0

okay, theres your reasoning, EP, lol:)

 Jul 9, 2020

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