In a 3-digit number, the hundreds digit is four more than the units digit, and the tens digit is three less than the sum of the other two digits. If the sum of all three digits in the number is 17, find the three digits.

(a - c) = 4,

b=(a + c) - 3,

(a + b + c) = 17, solve for a, b, c

a = 7, b = 7, c = 3, or:

773