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Solve the congruence \(2n \equiv 15 \pmod{47}\), as a residue modulo 47. (Give an answer between 0 and 46.)

 Aug 15, 2021
 #1
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The inverse of 2 modulo 4 is 17, so n = 15*17 = 255 = 20 (mod 47).

 Aug 15, 2021
 #2
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2n mod 47 ==15, solve for n

 

n ==31

2*31==62

62 mod 47 ==15

 Aug 15, 2021

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