If $n = 2^{10} \cdot 3^{14} \cdot 5^{8}$, how many of the natural-number factors of $n$ are multiples of 150

Guest Apr 6, 2020

#1**0 **

\(n = 2^{10} \cdot 3^{14} \cdot 5^{8}\)

150=5^2*3*2

We have \(2^9*3^{13}*5^6\) for each number of exponent, it can be up to that or less. or none. so we get 10*14*7 soo my answer is 980.

i think

MooMooooMooM Apr 6, 2020