+0  
 
+1
4
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avatar+826 

Fill in the coefficients:
n(n - 1)(n + 17)(n - 21)(n - 33) = n^5 + ___ n^4 + ___ n^3 + ___ n^2 + ___n + ___

 Jul 17, 2024
 #1
avatar+1768 
0

You get n^5 - 38n^4 + 108n^3 - 336n^2 + 7220n + 148060

 Jul 17, 2024
 #2
avatar+1908 
+1

First, let's use the FOIL method and combine two of the terms together. 

Combining two at a time, we get

\(n\left(n^2+16n-17\right)\left(n^2-54n+693\right)\)

 

Then, once again, combining the trinomials, we get

\(n\left(n^4-38n^3-188n^2+12006n-11781\right)\)

 

Distributing in the n. we finally find that

The final answwer is \(n^{5}-38n^{4}-188n^{3}+12006n^{2}-11781n\)

 

Thanksd! :)

 Jul 17, 2024
edited by NotThatSmart  Jul 17, 2024

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