Determine the largest possible integer n such that 942! is divisible by 80^n.
942! = 2^935 * 3^467 * 5^233 * 7^155.......etc.
80 ==2^4 x 5. Since the exponent of 5 ==233 and 80==2^4 x 5, it therefore follows that the largest possible value of n ==233. So that:
942! mod 80^233 ==0
