Find the smallest positive integer N such that
N &\equiv 4 \pmod{6}, \\
N &\equiv 4 \pmod{10}, \\
N &\equiv 4 \pmod{15}, \\
N &\equiv 4 \pmod{24}.
We are starting with this:
N≡4(mod6),N≡4(mod10),N≡4(mod15),N≡4(mod24).
We can rewrite this as:
N=6a+4N=10b+4N=15c+4N=24d+4
N−4=6aN−4=10bN−4=15cN−4=24d
Therefore, N - 4 is a factor of 6, 10, 15, and 24. To find the minimum value of N-4, we find the least common multiple of 6, 10, 15, 24. We can do this by listing out the factors:
6=2131
10=2151
15=3151
24=2331
N−4=lcm(6,10,15,24)=233151=120
Therefore, the least possible value of N is 124.