How many positive integers less than or equal to 6*7*8*9 solve the system of congruences:
m = 5 (mod 6)
m = 4 (mod 7)
m = 3 (mod 8)
m = 2 (mod 9)
m = 1 (mod 10)
6*7*8*9 ==3024
LCM(6, 7, 8, 9, 10)==2520
m ==2520n + 11, where n==0, 1, 2, 3.........etc.
When n=1, m==2520 + 11 ==2531 - the smallest m under 3024 that satisfies all 5 congruences.
