+1897 The smallest possible prime divisor a number can have is of course,
If we check the multiplication, we can see that 3 odd numbers can't possibly mulitply to be an even.
So, \(5^{19} * 7^{13} * 3^{31}\) is not divisble by 2.
The next smallest is 3.
The third term of the multiplication is \(3^{31}\)
This means, no matter what, this number has to be divisible by 3.
So 3 is our final answer.
Thanks! :)
