Find the six-digit number N such that when its digits are reversed, the result is equal to 4*N
4(abcdef)=fedcba
From the LHS a could be 1 or 2 but it can't be 1 because nothing times 4 has the last digit 1
SO
a is 2 which means f is 8 or 9 but it can't be 9 because nothing times 4 has the last digit 1
SO
a=2 and f=8
4(2bcde8)=8edcb2
SO
4(bcde8)= edcb2
b has to be 0, 1 or 2
4*8=32
so
4*e+3 = #b b must be 0,1,or 2
so
4*e+3= #0. #1, or #2
4*e = #7, #8, or #9
the only one that works is
4*e = #8
4*2 is 8 and 4*7 is 28 so e must be 2 or 7 but the smallest e can be is 4
SO
e=7
4(bcd78)= 7dcb2
Looking at that I can see that b must be 0 or 1 becaust anthing else is too big .. but 0 is too small
SO
b=1
4(1cd78)= 7dc12
subtract 40000 off both sides and you get
4(cd78)= 3dc12
now 4*78 = 312
so
4*(10c+d)+3 = 300+10d+c
40c+4d+3=300+ 10d+c
39C=6d+297
So C=9 and D=9
4(9978)= 39912 that works
4(219978)= 879912
N is the smaller one so
N=219978
Just as guest found with a computer program :) Thanks answer Guest.