Given that m - 2 is a positive integer that divides 3m^2 - 2m + 11, find the sum of all such values of m.
+65 "Given that m - 2 is a positive integer that divides 3m^2 - 2m + 11, find the sum of all such values of m."
For the last term to be an integer we must have m - 2 = 1, so m = 3; or m - 2 = 19, so m = 21
Hence sum = 3 + 21 = 24
+118609 Thanks Kakahi, 
I just want to look for myself 
Given that m - 2 is a positive integer that divides 3m^2 - 2m + 11, find the sum of all such values of m.
f(m)=3m^2 - 2m + 11
f(2)=12-4+11 = 19 that is the remainder/
19 is prime
19/(m-2) must be a whole number
m-2=19 or m-2=1
m=21 or m=3
Just like Kakashi said :) 
