We can solve this problem by defining variables and using a nice little trick.
First, let's set \(x = 0.031\overline{4}\). we are trying to put x in fractional form.
For that value of x, we have that \(10 x = 0.314\overline{4}\)
Now, we subtract x from 10x. We get
\(10x-x = 0.314\overline{4}-0.031\overline{4}\)
Since the repeating 4 cancels out, we are left with
\(9 x = 0.283\)
Now, we simplfy solve for x.
\(x = \frac{0.283}{9}\)
\(x=\frac{0.283}{9}\times \frac{1000}{1000}= \frac{283}{9000}\)
So, we have
\(0.031\overline{4} = \frac{283}{9000}\)
So 283/9000 is our final answer.
Thanks! :)
We can solve this problem by defining variables and using a nice little trick.
First, let's set \(x = 0.031\overline{4}\). we are trying to put x in fractional form.
For that value of x, we have that \(10 x = 0.314\overline{4}\)
Now, we subtract x from 10x. We get
\(10x-x = 0.314\overline{4}-0.031\overline{4}\)
Since the repeating 4 cancels out, we are left with
\(9 x = 0.283\)
Now, we simplfy solve for x.
\(x = \frac{0.283}{9}\)
\(x=\frac{0.283}{9}\times \frac{1000}{1000}= \frac{283}{9000}\)
So, we have
\(0.031\overline{4} = \frac{283}{9000}\)
So 283/9000 is our final answer.
Thanks! :)