Find the largest integer n for which 12^n evenly divides 20.
To add a bit, the reason 12^n can't be wholly divisable by 20 is because 20 = 2^2 * 5 and 12 = 2^2 * 3.
That means that 12^n will only have factors of 2 and 3 (assuming n is an integer).
Therefore, it will never be able to divide out the 5 in 20.
=^._.^=
Hello Guest!
\( n\in \mathbb Z\\ z=\dfrac{12^n}{20}\\\)
\(\large z\notin \mathbb Z\)
\(12 ^ n\) is in no case wholly divisible by 20.
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+14913 
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