Find the smallest positive integer such that the product of its digits is 60.
The prime factorization of 60 is: \(2^2 \times 5 \times 3 \).
The largest single-digit factor of 60 is 6. This will be our unit digit.
This means the remaining numbers must multiply out to 10, which means we need a 2 and 5.
Now, what's the smallest number possible with these 3 digits?
The prime factorization of 60 is: \(2^2 \times 5 \times 3 \).
The largest single-digit factor of 60 is 6. This will be our unit digit.
This means the remaining numbers must multiply out to 10, which means we need a 2 and 5.
Now, what's the smallest number possible with these 3 digits?