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Find the sum of the distinct prime factors of 123 - 47.

 Jun 15, 2024

Best Answer 

 #1
avatar+1280 
+1

First, let's subtract the to numbers and see what we get. 

We get \(123 - 47 = 76\)

 

Now, we need to find the prime factors of 76. 

 

When we factorize it, we get \(76 = 2^2 \cdot 19\)

 

This means there are only two distinct prime factors. \(2, 19\)

 

Adding these two up, we get \(19+2=21\)

 

So 21 is our final answer!

 

Thanks! :)

 Jun 16, 2024
 #1
avatar+1280 
+1
Best Answer

First, let's subtract the to numbers and see what we get. 

We get \(123 - 47 = 76\)

 

Now, we need to find the prime factors of 76. 

 

When we factorize it, we get \(76 = 2^2 \cdot 19\)

 

This means there are only two distinct prime factors. \(2, 19\)

 

Adding these two up, we get \(19+2=21\)

 

So 21 is our final answer!

 

Thanks! :)

NotThatSmart Jun 16, 2024

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