How many 6-digit numbers have the property that the sum of the first 3 digits = the sum of the last 3 digits and that it is a multiple of 1009? Thank you for help.
I think this is a computer coding assignment. Because there are 900,000 numbers to be checked !! Even if you were to narrow it down to just the multiples of 1009, you would still have almost 900 numbers to check !!.
I agree with the above Guest #1. This is a job for a computer code. I wrote a short code and it gives the following result:
116035 125116 161440 170521 188683 197764 232070 241151 250232 268394 277475 286556 295637 357186 366267 375348 384429 429834 438915 455059 491383 509545 518626 527707 554950 571094 580175 607418 625580 634661 643742 652823 661904 705291 714372 723453 732534 741615 759777 768858 777939 803164 812245 821326 830407 839488 848569 884893 893974 901037 910118 919199 973685 982766 991847 Total = 55 such numbers
