(a) Find the last two digits of $9*7*11$.
(b) Find the last two digits of $4^{5^6}$. (By convention, exponent towers are evaluated from the top down, so $4^{5^6} = 4^{(5^6)}$.)
(a) For this part, it isn't too hard to multiply the numbers out.
All 3 numbers are very small, so the product is not large.
We just have \(9*7*11=693\), so 93 is our answer.