Find all natural numbers, which when divided by 7, leave the same number for the quotient and the remainder.
a=1; c=int(a / 7); b=a%7;if(c==b, goto4, goto5);printa,c,b; a++;if(a<1000, goto1, 0)
n q r, where n=Number, q =Quotient, r = Remainder.
8 1 1 16 2 2 24 3 3 32 4 4 40 5 5 48 6 6
Think of it like this:
(1*7 + 1)/7 8
(2*7 + 2)/7 16
(3*7 + 3)/7 24
(4*7 + 4)/7 32
(5*7 + 5)/7 40
(6*7 + 6)/7 48
