x,y,z are three consecutive positive odd integers that satisfy y^2 - x^2 = 384. Find the value of z.
Let y = n x = n - 2 and z = n + 2
So
n^2 - ( n - 2)^2 = 384
n^2 - n^2 + 4n - 4 = 384
4n = 384 + 4
4n = 388
n = 388/ 4 = 97
So
z = n + 2 = 99
well, y must be greater than x, so x + 2 = y.
y2−x2=384 and x+2=y
so solving that system of equations... u get x=95,y=97
so 97 + 2 = 99