#3**+11 **

59. Let N be rhe number.......so we have

N - log_{b} 1 =

N - 0 =

N always true

60. Never true.....

61. We are using log a^2 = 2 log a ......always true

62. Not generally true......unless the log itself can be easily calculated......example.....

log_{3}9 + log_{2}8 =

2 + 3 = 5

63. log_{6} 16 / log_{6} 8

Using the change-of-base rule, we have [log 16/ log 6]/ [log 8/ log6] =

[log 16/ log 6]* [log 6/ log8] = log 16/ log 8 = log_{8} 16 = 4/3

64. log (log N)= N....I don't believe this is ever true

CPhill
Dec 14, 2016

#1**+10 **

Come on rarinstraw, we are not here to do all your homework for you.

Try them with some numbers ans see what happens. 59 looks pretty easy.

63 is easy

If you look at the formulary on this site the log rules are there.

Melody
Dec 14, 2016

#3**+11 **

Best Answer

59. Let N be rhe number.......so we have

N - log_{b} 1 =

N - 0 =

N always true

60. Never true.....

61. We are using log a^2 = 2 log a ......always true

62. Not generally true......unless the log itself can be easily calculated......example.....

log_{3}9 + log_{2}8 =

2 + 3 = 5

63. log_{6} 16 / log_{6} 8

Using the change-of-base rule, we have [log 16/ log 6]/ [log 8/ log6] =

[log 16/ log 6]* [log 6/ log8] = log 16/ log 8 = log_{8} 16 = 4/3

64. log (log N)= N....I don't believe this is ever true

CPhill
Dec 14, 2016