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# Old 'prank' question

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Here is an old one that was reported.

Maybe someone might be interested in working out it is a real, answerable question.

https://web2.0calc.com/questions/as-a-prank

Please answer on the original thread and then report here that you have done so.

Since everyone has answered here I will include the question:

As a prank, Tim decides to steal Nathan's fork at dinner, but so he doesn't get caught, he convinces other people to do it for him. On Monday, he convinces Joe to do it. On Tuesday, he could get either Ambie or John to do it. On Wednesday, he can't convince any of those three people to do it, but there are five other people he could convince to do it. On Thursday, none of those five will do it, nor the first three, but there are four others who are willing. Finally, on Friday, Tim does it himself. How many different combinations of people could Tim involve in the prank?

Jul 18, 2020
edited by Melody  Jul 19, 2020

### 8+0 Answers

#1
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40???

Jul 18, 2020
#2
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1t is 1*2*5*4=40 so there are 40 combinitions

Jul 18, 2020
#3
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I thought the original answer was correct.....since no other one would do it and Tim had to do it himself.....there are no other combos ????/

Jul 18, 2020
#5
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I'm not really sure if it's 0 or 40 though

jimkey17  Jul 18, 2020
#6
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Yeah, I agree.

Guest Jul 18, 2020
#4
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It is 40:

1 way for the first

2 for the second

5 for the third

4 for the last one

1*2*5*4=\(\boxed {40}\)

Jul 18, 2020
#7
+26802
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.....but the question states he cannot get anyone to do it !    So  no combos ?

ElectricPavlov  Jul 18, 2020
#8
+110727
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I do not think the question states he cannot get anyone to help.

But it does state that he is trying to get someone to do it for him. I think the inference is that it is a one person job.

He finally does it himself so It seems reasonably to assume that no one was available to do it for him on the day he chose for it to be done.

Melody  Jul 19, 2020