+91 A circle has the points A(h,k) , B(x,y) and C (x-h, y-k). Use Pythagorean Theorem to derive the equation of circle with center (h,k) and radius r. Show each step of your derivation.
+118687 Hi Metallica22,
You know we really like it when people ask us to explain our answers better. :)
It means someone is really trying to learn from us :)
Maybe this pic will help.
From the picture you can see that \(r^2=(x-h)^2+(y-k)^2\)
The question is worded badly and I am not sure if I have given the answer that is really most wanted.
I have not used the point C......
+118687 A circle has the points A(h,k) , B(x,y) and C (x-h, y-k). Use Pythagorean Theorem to derive the equation of circle with center (h,k) and radius r. Show each step of your derivation.
centre (h,k) radius r and (x,y) is on the circumference
let the radius be the hyporenuse of a right angled triangle. The lengths of the other sides will be |x-h| and |y-k|
\(r^2=(x-h)^2+(y-k)^2\)
finished :///
+118687 Hi Metallica22,
You know we really like it when people ask us to explain our answers better. :)
It means someone is really trying to learn from us :)
Maybe this pic will help.
From the picture you can see that \(r^2=(x-h)^2+(y-k)^2\)
The question is worded badly and I am not sure if I have given the answer that is really most wanted.
I have not used the point C......
+91 but how do you show a step by step derivation of that equation from pythagorean's theorem? Do I do AB^2=AC^2+BC^2 and then put in (x-h)^2+(y+k)^2=r^2
