On a circle of radius 8 feet, give the degree measure of the angle that would subtend an arc of length 3 feet. Round your answer to the near

On a circle of radius r= 8 feet, give the degree measure of the angle \(\alpha\) that would subtend an arc of length 3 feet. Round your answer to the nearest hundredth, or two decimal places .

\(\large arc=2\pi r\cdot \frac{\alpha}{360deg}\)

\(\large \alpha=\frac{arc \cdot 360deg }{2\cdot \pi\cdot r}\)

\(\large \alpha=\frac{3ft \cdot 360deg }{2\cdot \pi\cdot 8ft}\)

\(\large \alpha=21.49\ deg\)

\(\large The \ arc \ of \ the \ length \ 3 feet \ is \ formed \ by \ an \ angle \ of \ 21.49\ deg.\)

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Thanks asinus....here's another way

s  = r * theta in radians  .......where s is the arc length and r is the radius...so we have  

3  = 8 * theta

3/8  = theta  ......  convert to degrees

3/8  * 180 / pi   ≈ 21.486°