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On the day after Halloween, Kabir had 5 times as much candy as Sam. If Kabir gives 18 pieces of candy to Sam, they will each have the same amount. How many pieces of candy do they have in all?

 May 8, 2021
edited by Guest  May 8, 2021
 #1
avatar+437 
+3

ok, not thay hard. we can make a variable.

 

say x = pieces of candy Sam has.

so Kabir has 5x

and the total is x + 5x = 6x

 

then we know that 5x - 18 = 3x        (the 3x is from 6x/2)

\(5x-18=3x \)

\(5x=3x+18\)

\(2x=18\)

\(x=9\)

 

so the total is 6x, 6 * 9 = 54.

 May 10, 2021
 #2
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5x = Kabir's candy

 

5x - 18 = 3x

 

5x - 18 = 3x

 

2x - 18 = 0

 

2x = 18

 

x = 9

 

So:

 

6x = Total

 

6 * (9) = Total

 

56 = Total

 

 

The total amount of candy that both boys have is 56 pieces of candy.

Guest May 14, 2021
 #3
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*54*

Guest May 14, 2021
 #4
avatar+186 
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k=5s and s+18=k-18or k=s+36 so now's+36=5s or 4s=36 or s=9,so Sam had 9,Kabir had 5*9=45 and total 9+45=54 candy .

 May 14, 2021
 #5
avatar+511 
0

On the day after Halloween, Kabir had 5 times as much candy as Sam. If Kabir gives 18 pieces of candy to Sam, they will each have the same amount. How many pieces of candy do they have in all?

 

Let k = number of candies Kabir has.

Let s = number of candies Sam has.

 

We have $k = 5s \qquad$ (1)

We also have $k-18=s+18 \qquad$ (2)

(1) * (2) => $5s - 18 = s + 18$

$4s = 36$

$s = 9 \qquad$ (3)

(3) & (1) => $k = 45 \qquad$ (4)

(3) + (4) => $9 + 45 = \boxed{54}$

 

laugh

 May 14, 2021
 #6
avatar+134 
+1

https://web2.0calc.com/questions/asap-math_1

 

I have posted an answer here :)

 May 17, 2021

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