On the day after Halloween, Kabir had 5 times as much candy as Sam. If Kabir gives 18 pieces of candy to Sam, they will each have the same amount. How many pieces of candy do they have in all?

Guest May 8, 2021

edited by
Guest
May 8, 2021

#1**+3 **

ok, not thay hard. we can make a variable.

say x = pieces of candy Sam has.

so Kabir has 5x

and the total is x + 5x = 6x

then we know that 5x - 18 = 3x (the 3x is from 6x/2)

\(5x-18=3x \)

\(5x=3x+18\)

\(2x=18\)

\(x=9\)

so the total is 6x, 6 * 9 = 54.

mworkhard222 May 10, 2021

#4**0 **

k=5s and s+18=k-18or k=s+36 so now's+36=5s or 4s=36 or s=9,so Sam had 9,Kabir had 5*9=45 and total 9+45=54 candy .

KINGCASH May 14, 2021

#5**0 **

On the day after Halloween, Kabir had 5 times as much candy as Sam. If Kabir gives 18 pieces of candy to Sam, they will each have the same amount. How many pieces of candy do they have in all?

Let k = number of candies Kabir has.

Let s = number of candies Sam has.

We have $k = 5s \qquad$ (1)

We also have $k-18=s+18 \qquad$ (2)

(1) * (2) => $5s - 18 = s + 18$

$4s = 36$

$s = 9 \qquad$ (3)

(3) & (1) => $k = 45 \qquad$ (4)

(3) + (4) => $9 + 45 = \boxed{54}$

MathProblemSolver101 May 14, 2021