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# one last interest rates problem

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Jose invested \$50,000 for 2 years at an annual interest rate of 4 percent compounded yearly. Patricia invested \$50,000 for the same period of time, at the same interest rate, but the interest was compounded quarterly. To the nearest dollar, how much more money did Patricia's investment earn than that of Jose?

Thanks a bunch!

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F=   P (1=i)^n     Where F = future value  P = initial value (50000)   i= periodic interest   n = number of periods

Jose :   F = 50, 000 (1+ .04)^2  = 54,080

Patricia  i = periodic interest where the period is 3 mos (4 times a year)  .04/4 = .01   and periods = 2 yrs x 4/yr = 8

F= 50,000 (1 +.01)^8 = 54142.84

Difference =62.84   to the nearest dollar , Patricia earned \$64 more than Jose.

Dec 3, 2017
edited by ElectricPavlov  Dec 3, 2017
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Thanks but, you mean 63?  Haha!

edited by AnonymousConfusedGuy  Dec 3, 2017
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Yup..... that is what I 'meant'......oops !  Guess I'm not too good at this math stuff ElectricPavlov  Dec 4, 2017