Hello, I just have one math equation that I need to solve quickly. I appreciate all your help.

At an ocean depth of 20 m, a buoy bobs up and then down 2 m from the ocean's depth. Four seconds pass from when the buoy is at its highest and lowest points. Assume at *x* = 0, the buoy is at normal ocean depth.

The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

Guest Feb 9, 2018

#1**0 **

We'll use a sin graph since at x=0 the buoy is at the y midline....

the period is 8 seconds (highest point to lowest point and back to highest point)

Frequency is 1/period 1/8

Starts at 20 (sine wave shifted up 20 m)

Amplitude 2 (up 2 meters then down 2 meters below norma ocean depth) .....( I think this is what you meant in your question.....if it bobs UP 2m then back to normal depth then down 2m)

2sin((2pi x)/8) + 20

Picture:

ElectricPavlov
Feb 9, 2018

edited by
Guest
Feb 9, 2018