+0  
 
0
234
1
avatar

Hello, I just have one math equation that I need to solve quickly. I appreciate all your help.

 

At an ocean depth of 20 m, a buoy bobs up and then down 2 m from the ocean's depth.  Four seconds pass from when the buoy is at its highest and lowest points. Assume at x = 0, the buoy is at normal ocean depth.

The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

Guest Feb 9, 2018
 #1
avatar+12565 
0

We'll use a sin graph since at x=0 the buoy is at the y midline....

the period is 8 seconds  (highest point to lowest point and back to highest point)

Frequency is   1/period     1/8

Starts at 20  (sine wave shifted up 20 m)

Amplitude  2   (up 2 meters then down 2 meters below norma ocean depth)    .....( I think this is what you meant in your question.....if it bobs UP 2m then back to normal depth then down 2m)

 

2sin((2pi x)/8)   + 20

 

Picture:

ElectricPavlov  Feb 9, 2018
edited by Guest  Feb 9, 2018

14 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.