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Hello, I am just really bad with probability questions. I'm sorry if I am asking too much, but I really could use all the help I can get. So if you can help me out, that would be great. Thanks for taking the time to help me! :)

 

Heres the question--> You are playing a game that involves rolling two fair dice (number cubes) numbered 1 through 6.

 

The rules of the game are altered so that the number of points you score is the product of the two dice unless you roll doubles in which case you lose twice the product. For example, if you roll a 3 and a 5 you gain 15 points, but if you roll two 4’s you lose 2*4*4=32 points. What is the expected value for one turn. Show your work!

Guest May 20, 2018
 #1
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+1

all the non-double/non-repeated options should be listed

1x2=2  

1x3=3

1x4=4

1x5=5

1x6=6

2x3=6

2x4=8

2x5=10

2x6=12

3x4=12

3x5=15

3x6=18

4x5=20

4x6=24

5x6=30

 

as you can see 6 and 12 are listed twice,

those would be the expected value and both equaly likely to happen

Guest May 21, 2018
 #4
avatar+92617 
+1

The expected value is 4 and 2/3

 

 

Melody  May 21, 2018

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