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Let f(x)=x^2-16 and g(x)=x^2-6x+8. 

What is (f/g)(x)?

Hint: You will factor using difference of squares and a=1 methods

 Apr 8, 2019

Best Answer 

 #1
avatar+19929 
0

(x^2-16)  / (x^2-6x+8)   =

 

(x-4)(x+4) / ( x -4)(x-2)         (x cannnot equal 4)

 

The numerator and denominator (x-4)'s cancel and you are left with:

 

(x+4) /(x-2)      x cannot equl 4   or 2

 Apr 8, 2019
 #1
avatar+19929 
0
Best Answer

(x^2-16)  / (x^2-6x+8)   =

 

(x-4)(x+4) / ( x -4)(x-2)         (x cannnot equal 4)

 

The numerator and denominator (x-4)'s cancel and you are left with:

 

(x+4) /(x-2)      x cannot equl 4   or 2

ElectricPavlov Apr 8, 2019
 #2
avatar+1009 
0

(f/g)(x)=f(x)/g(x)

x^2-16/x^2-6x+8

(x-4)(x+4)/(x-4)(x-2)

(x+4)/(x-2) = (f/g)(x)

 

You are very welcome!

:P

 Apr 8, 2019

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