+0  
 
0
512
2
avatar

Our club has 20 members, 10 boys and 10 girls. In how many ways can we choose a president and a vice-president if they must be of the same gender? Assume no one can hold both offices.

Guest Mar 18, 2015

Best Answer 

 #2
avatar+93629 
+5

I think it is 2 of the 10 boys OR 2 of the ten girls, and order counts so that is

10*9 + 10*9 = 180

 

or

10P2 + 10P2 = 180

Melody  Mar 19, 2015
 #1
avatar+89803 
+5

We could choose 2 of 10 boys and the same wth the girls....so we have

[C(10,2)]^2 = 2025 ways

 

  

CPhill  Mar 18, 2015
 #2
avatar+93629 
+5
Best Answer

I think it is 2 of the 10 boys OR 2 of the ten girls, and order counts so that is

10*9 + 10*9 = 180

 

or

10P2 + 10P2 = 180

Melody  Mar 19, 2015

5 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.