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# Parabola question

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Find the vertex of the graph of the equation y=-2x^2+18x-15+x^2-6x+1 .

Apr 15, 2022

#1
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Combining like terms, we find the equation of the parabola is: $$y = -x^2+12x-14$$

The vertex/axis of symmetry appears at $$x = {b \over 2a}$$. Plugging in the values, we see that the vertex appears when $$x = 6$$

Plugging in $$x = 6$$, we find the vertex is $$\color{brown}\boxed{(6,22)}$$

Apr 15, 2022

#1
+2437
+1

Combining like terms, we find the equation of the parabola is: $$y = -x^2+12x-14$$

The vertex/axis of symmetry appears at $$x = {b \over 2a}$$. Plugging in the values, we see that the vertex appears when $$x = 6$$

Plugging in $$x = 6$$, we find the vertex is $$\color{brown}\boxed{(6,22)}$$

BuilderBoi Apr 15, 2022