Combining like terms, we find the equation of the parabola is: \(y = -x^2+12x-14\)
The vertex/axis of symmetry appears at \(x = {b \over 2a}\). Plugging in the values, we see that the vertex appears when \(x = 6\)
Plugging in \(x = 6\), we find the vertex is \(\color{brown}\boxed{(6,22)}\)
Combining like terms, we find the equation of the parabola is: \(y = -x^2+12x-14\)
The vertex/axis of symmetry appears at \(x = {b \over 2a}\). Plugging in the values, we see that the vertex appears when \(x = 6\)
Plugging in \(x = 6\), we find the vertex is \(\color{brown}\boxed{(6,22)}\)