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Find the vertex of the graph of the equation y=-2x^2+18x-15+x^2-6x+1 .

 Apr 15, 2022

Best Answer 

 #1
avatar+2437 
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Combining like terms, we find the equation of the parabola is: \(y = -x^2+12x-14\)

 

The vertex/axis of symmetry appears at \(x = {b \over 2a}\). Plugging in the values, we see that the vertex appears when \(x = 6\)

 

Plugging in \(x = 6\), we find the vertex is \(\color{brown}\boxed{(6,22)}\)

 Apr 15, 2022
 #1
avatar+2437 
+1
Best Answer

Combining like terms, we find the equation of the parabola is: \(y = -x^2+12x-14\)

 

The vertex/axis of symmetry appears at \(x = {b \over 2a}\). Plugging in the values, we see that the vertex appears when \(x = 6\)

 

Plugging in \(x = 6\), we find the vertex is \(\color{brown}\boxed{(6,22)}\)

BuilderBoi Apr 15, 2022

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