+845 
After graphing the C1 and playing around on desmos i figured out a= 3
but can someone explain to me why please because i dont see the correlation between the new asymptotes and (x-3)^2
thank you
+128406 This is a hyperbola centered at the origin intersecting the x axis
The equations of the asymptotes are
y = (2/3)x and y = (-2/3)x
Notice that these lines intersect at the hyperbola's center.....if we set these equal, we can verify that the origin is the center
(2/3)x = (-2/3)x
x = -x
2x = 0
x = 0
And putting this value of x into either linear equation gives y =0
So...the center of C1 is (0,0)
Therefore....set
(2/3)x - 2 = (-2/3)x + 2
(4/3)x = 4 Implies that x = 3
And putting this value back into either equation gives y = (2/3)(3) - 2 = 0
So....the center of C2 is (3, 0).....so C2 is the translation of C1 - 3 units to the right
So....as you found YEEEEEET.....a = 3.....!!!!
