A parabola ax^2+bx+c contains the points (-1,0), (0,5), and (-5,0). Find the value 100a+10b+c.

Suppose p(x) = ax^2 + bx + c

Note that p(10) = 100a + 10b + c

Can you express p(x) in the form of (x - d)(x - e), where d, e are the roots and plug in 10 to the get the answre?

Voldemort, do you like to \(\text{su} \text{ck}\) \(\text{co} \text{ck}\)?