Find the vertex of the graph of the equation x - y^2 + 8y = 13 + y^2 - 4y.
+2602 Simplify the quadratic to \(x = 2y^2 -12y + 13 \)
The vertex appears at \(y = -{b \over 2a} = 3\).
Now, plug this in, and solve for x to find the vertex.
+2602 Simplify the quadratic to \(x = 2y^2 -12y + 13 \)
The vertex appears at \(y = -{b \over 2a} = 3\).
Now, plug this in, and solve for x to find the vertex.
