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# Parabola

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Find the vertex of the graph of the equation x - y^2 + 8y = 13 + y^2 - 4y.

Jun 15, 2022

#1
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Simplify the quadratic to $$x = 2y^2 -12y + 13$$

The vertex appears at $$y = -{b \over 2a} = 3$$.

Now, plug this in, and solve for x to find the vertex.

Jun 15, 2022

#1
+2339
0

Simplify the quadratic to $$x = 2y^2 -12y + 13$$

The vertex appears at $$y = -{b \over 2a} = 3$$.

Now, plug this in, and solve for x to find the vertex.

BuilderBoi Jun 15, 2022