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Find the vertex of the graph of the equation x - y^2 + 8y = 13 + y^2 - 4y.

 Jun 15, 2022

Best Answer 

 #1
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Simplify the quadratic to \(x = 2y^2 -12y + 13 \)

 

The vertex appears at \(y = -{b \over 2a} = 3\).

 

Now, plug this in, and solve for x to find the vertex. 

 Jun 15, 2022
 #1
avatar+2448 
0
Best Answer

Simplify the quadratic to \(x = 2y^2 -12y + 13 \)

 

The vertex appears at \(y = -{b \over 2a} = 3\).

 

Now, plug this in, and solve for x to find the vertex. 

BuilderBoi Jun 15, 2022

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